82 lines
2.6 KiB
Python
Vendored
82 lines
2.6 KiB
Python
Vendored
# MIT License
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#
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# Copyright The SCons Foundation
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#
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# Permission is hereby granted, free of charge, to any person obtaining
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# a copy of this software and associated documentation files (the
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# "Software"), to deal in the Software without restriction, including
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# without limitation the rights to use, copy, modify, merge, publish,
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# distribute, sublicense, and/or sell copies of the Software, and to
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# permit persons to whom the Software is furnished to do so, subject to
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# the following conditions:
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#
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# The above copyright notice and this permission notice shall be included
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# in all copies or substantial portions of the Software.
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#
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# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY
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# KIND, EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE
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# WARRANTIES OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
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# NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE
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# LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION
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# OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION
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# WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
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"""
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MS Compilers: .Net Framework support
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"""
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import os
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import re
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from .common import read_reg, debug
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# Original value recorded by dcournapeau
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_FRAMEWORKDIR_HKEY_ROOT = r'Software\Microsoft\.NETFramework\InstallRoot'
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# On SGK's system
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_FRAMEWORKDIR_HKEY_ROOT = r'Software\Microsoft\Microsoft SDKs\.NETFramework\v2.0\InstallationFolder'
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def find_framework_root():
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# XXX: find it from environment (FrameworkDir)
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try:
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froot = read_reg(_FRAMEWORKDIR_HKEY_ROOT)
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debug("Found framework install root in registry: %s", froot)
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except OSError:
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debug("Could not read reg key %s", _FRAMEWORKDIR_HKEY_ROOT)
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return None
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if not os.path.exists(froot):
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debug("%s not found on fs", froot)
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return None
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return froot
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def query_versions():
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froot = find_framework_root()
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if froot:
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contents = os.listdir(froot)
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l = re.compile('v[0-9]+.*')
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versions = [e for e in contents if l.match(e)]
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def versrt(a,b):
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# since version numbers aren't really floats...
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aa = a[1:]
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bb = b[1:]
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aal = aa.split('.')
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bbl = bb.split('.')
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# sequence comparison in python is lexicographical
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# which is exactly what we want.
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# Note we sort backwards so the highest version is first.
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return (aal > bbl) - (aal < bbl)
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versions.sort(versrt)
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else:
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versions = []
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return versions
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# Local Variables:
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# tab-width:4
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# indent-tabs-mode:nil
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# End:
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# vim: set expandtab tabstop=4 shiftwidth=4:
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